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Crane Operator Certification Exam Prep · Question

A 2,000 kg load is lifted using a two-leg bridle sling. Each sling leg is 4 metres long, and the distance between the lifting points on the load is also 4 metres. Calculate the approximate tension in each sling leg.

With sling legs of 4m and a spread of 4m, the head room is calculated using Pythagoras: sqrt(4^2 - (4/2)^2) = sqrt(16-4) = sqrt(12) = 3.46 m. The sling angle is

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Question: A 2,000 kg load is lifted using a two-leg bridle sling. Each sling leg is 4 metres long, and the distance between the lifting points on the load is also 4 metres. Calculate the approximate tension in each sling leg.

Answer options:

  • 1,000 kg (10 kN) ✅ 1,155 kg (11.3 kN)
  • 2,000 kg (19.6 kN)
  • 866 kg (8.5 kN)

Correct answer: 1,155 kg (11.3 kN)

Explanation: With sling legs of 4m and a spread of 4m, the head room is calculated using Pythagoras: sqrt(4^2 - (4/2)^2) = sqrt(16-4) = sqrt(12) = 3.46 m. The sling angle is arcsin(3.46/4) = 60 degrees. Tension = (Load / Number of Legs) / cos(Sling Angle). So, (2000 kg / 2) / cos(60°) = 1000 kg / 0.866 = 1154.7 kg. This is a common rigging calculation derived from CSA Z150 principles.

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