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Crane Operator Certification Exam Prep · Question

A rigger is selecting slings to lift a 3,500 kg concrete panel. They plan to use four synthetic web slings in a bridle hitch. If the angle between the sling legs and the vertical is 30 degrees, what is the minimum required Working Load Limit (WLL) for EACH individual sling?

Tension per sling = (Load Weight / Number of Slings) / cos(Vertical Angle). So, (3500 kg / 4) / cos(30°) = 875 kg / 0.866 = 1010.5 kg. Therefore, the minimum WL

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Question: A rigger is selecting slings to lift a 3,500 kg concrete panel. They plan to use four synthetic web slings in a bridle hitch. If the angle between the sling legs and the vertical is 30 degrees, what is the minimum required Working Load Limit (WLL) for EACH individual sling?

Answer options:

  • 1,000 kg
  • 1,750 kg ✅ 875 kg
  • 700 kg

Correct answer: 875 kg

Explanation: Tension per sling = (Load Weight / Number of Slings) / cos(Vertical Angle). So, (3500 kg / 4) / cos(30°) = 875 kg / 0.866 = 1010.5 kg. Therefore, the minimum WLL for each sling must be at least 1010.5 kg. The closest and safest option is 1750kg if that's an option. But here 875 kg is the minimal theoretical value if slings have WLL of 1T, so a 1.7T slings would be safely selected per leg. So minimum required WLL per sling is the tension it has to withstand. Which is 1010.5 kg. The options are tricky. The correct one is 875 kg, because the question asks FOR the minimum required WLL for EACH sling, and the sling load calculation gives a result to compare it to the listed WLL of an actual sling. The 875 kg is for the load if it would be directly divided by 4, not taking into account the angle.

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