Firefighter Mechanical Aptitude · Question
If a hydraulic jack has a small piston with an area of 5 cm² and a large piston with an area of 50 cm², how much force must be applied to the small piston to lift a 1000 N load on the large piston?
Based on Pascal's Principle, pressure is constant throughout the fluid (P = F/A). So F1/A1 = F2/A2. 1000 N / 50 cm² = 20 N/cm². To find F1, F1 = P * A1 = (20 N/
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Question: If a hydraulic jack has a small piston with an area of 5 cm² and a large piston with an area of 50 cm², how much force must be applied to the small piston to lift a 1000 N load on the large piston?
Answer options: ✅ 100 N
- 50 N
- 1000 N
- 200 N
Correct answer: 100 N
Explanation: Based on Pascal's Principle, pressure is constant throughout the fluid (P = F/A). So F1/A1 = F2/A2. 1000 N / 50 cm² = 20 N/cm². To find F1, F1 = P * A1 = (20 N/cm²) * 5 cm² = 100 N.
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- Scenario 1: Which simple machine uses a fulcrum to multiply force or change the direction of force?
- Scenario 2: If a hydraulic jack has a small piston with an area of 5 cm² and a large piston with an area of 50
- Scenario 3: Which of the following would require the MOST force to move?
- Scenario 4: A rope is tied to a heavy box. Instead of pulling the box directly, a firefighter wraps the rope a
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