Heavy Equipment Operator Certification Exam Prep · Question
During a pre-operational inspection of an excavator on a construction site near Toronto, you notice the hydraulic oil level is below the minimum mark on the sight glass. The manufacturer's manual specifies a operating oil capacity of 250 litres. Approximately how much hydraulic fluid should be added if the level is 1/4 of the way between the MIN and MAX marks, and the MIN to MAX range represents 10% of the total capacity?
The MIN to MAX range is 10% of 250 litres, which is 25 litres. If the current level is 1/4 of the way up from MIN, it means 3/4 of the range is needed. (3/4) *
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Question: During a pre-operational inspection of an excavator on a construction site near Toronto, you notice the hydraulic oil level is below the minimum mark on the sight glass. The manufacturer's manual specifies a operating oil capacity of 250 litres. Approximately how much hydraulic fluid should be added if the level is 1/4 of the way between the MIN and MAX marks, and the MIN to MAX range represents 10% of the total capacity?
Answer options:
- 18.75 litres ✅ 6.25 litres
- 25 litres
- 12.5 litres
Correct answer: 6.25 litres
Explanation: The MIN to MAX range is 10% of 250 litres, which is 25 litres. If the current level is 1/4 of the way up from MIN, it means 3/4 of the range is needed. (3/4) * 25 litres = 18.75 litres to reach MAX, or (1/4)*25 = 6.25 litres above MIN. To reach the minimum operating level, we need to add enough to get to the 'MIN' itself, then more to get it within the operating range. Given it's below MIN, and the MIN-MAX represents 10% of total capacity (25L), to bring it from 1/4 of the way between MIN and MAX up to the actual MIN mark, you'd be adding to reach the MIN, and then topping up. However, if the question implies 'how much is missing from the MIN mark to the current level', it means from MIN to present level. If the level is 1/4 between MIN and MAX, it is technically above the MIN. If the level is below the MIN and needs to reach the MIN mark to start, and the MIN-MAX spread is 25 litres, and the level observed is 1/4 of that spread below the MIN, then you're missing 0.25 * 25 L = 6.25 L to get to the MIN mark. The question implies the level is below minimum and you are 'adding' fluid. Assuming the level is 1/4 of the way towards the MIN from empty, or if it says '1/4 of the way between the MIN and MAX' when it should be at least at MIN, the most logical interpretation for 'how much to add if below minimum' when 1/4 of the way between min and max is that it's sitting at the minimum, and needs topping up to at least the minimum operable level, but if it is below minimum overall. A more accurate wording might be 'level is 1/4 of the way below the MIN mark'. If it is 1/4 of the way between the MIN and MAX, it is above the MIN mark. Re-evaluating the premise: 'below the minimum mark' and '1/4 of the way between MIN and MAX'. These contradict. Let's assume the spirit of the question is 'how much is missing from the MIN mark if the full MIN-MAX range is X, and it's observed as 1/4 of X below the MIN mark'. Given the options, '6.25 litres' suggests this interpretation by calculating 0.25 * 25 L. If it is 1/4 of the way between MIN and MAX, it is not below minimum, it is within. Therefore, the interpretation must be that it is 1/4 of the specified range below the minimum mark. 10% of 250 L is 25 L for the MIN-MAX range. 1/4 of that range is 6.25 L. So, 6.25 L is needed to reach the MIN mark.
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