While performing field work, which action correctly applies Q20 calculation Q20 = Qf·((Hr-20)/(Hr-Hf))^0.54 (scenario variant 26)?

Question: While performing field work, which action correctly applies Q20 calculation Q20 = Qf·((Hr-20)/(Hr-Hf))^0.54 (scenario variant 26)?

Answer options:

• Treat any anomaly in Q20 calculation Q20 = Qf·((Hr-20)/(Hr-Hf))^0.54 (scenario variant 26) as a non-deficiency regardless of severity ✅ The requirement defined for Q20 calculation Q20 = Qf·((Hr-20)/(Hr-Hf))^0.54 (scenario variant 26) is met and recorded on the ITM report
• Defer all action on Q20 calculation Q20 = Qf·((Hr-20)/(Hr-Hf))^0.54 (scenario variant 26) to the next annual inspection without notification
• Apply manufacturer marketing literature instead of the code for Q20 calculation Q20 = Qf·((Hr-20)/(Hr-Hf))^0.54 (scenario variant 26)

Correct answer: The requirement defined for Q20 calculation Q20 = Qf·((Hr-20)/(Hr-Hf))^0.54 (scenario variant 26) is met and recorded on the ITM report

Explanation: Per ULC-S543 / MUTCD Part 6 (traffic control), Q20 calculation Q20 = Qf·((Hr-20)/(Hr-Hf))^0.54 governs the correct procedure. Distractors omit or contradict the standard.