CFAA Fire Alarm Technician · Question
A circuit has a total resistance of 40 Ohms and is connected to a 24VDC source. What is the total power dissipation of the circuit?
I = V/R. 24 / 40 = 0.6A. P = V*I = 24 * 0.6 = 14.4W. CFAA Manual S1-Ch2.
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Question: A circuit has a total resistance of 40 Ohms and is connected to a 24VDC source. What is the total power dissipation of the circuit?
Answer options:
- 0.6 W
- 1.67 W ✅ 14.4 W
- 24.0 W
Correct answer: 14.4 W
Explanation: I = V/R. 24 / 40 = 0.6A. P = V*I = 24 * 0.6 = 14.4W. CFAA Manual S1-Ch2.
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Question explanations
- The primary power for a fire alarm system must be:
- If a 120VAC primary power circuit for a fire alarm control unit is consuming 60 Watts of power, what is the cu
- In a steady-state DC circuit, if the conductor length is doubled while maintaining voltage and wire gauge, wha
- A resistor is rated at 10 Watts at 24VDC. If the voltage drops to 20VDC, what is the new power dissipation?
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