Crane Operator Certification Exam Prep · Question
A crane operator is using a two-leg bridle sling to lift a structural steel beam weighing 8000 kg. The angle between each sling leg and the horizontal is 60 degrees. What is the approximate tension on each individual sling leg?
When the angle is given from the horizontal, the formula for tension (T) in each leg is T = (Load Weight) / (2 * sin(Angle from Horizontal)). So, T = 8000 kg /
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Question: A crane operator is using a two-leg bridle sling to lift a structural steel beam weighing 8000 kg. The angle between each sling leg and the horizontal is 60 degrees. What is the approximate tension on each individual sling leg?
Answer options:
- 4000 kg ✅ 4619 kg
- 8000 kg
- 2309 kg
Correct answer: 4619 kg
Explanation: When the angle is given from the horizontal, the formula for tension (T) in each leg is T = (Load Weight) / (2 * sin(Angle from Horizontal)). So, T = 8000 kg / (2 * sin(60°)) = 8000 kg / (2 * 0.866) = 8000 kg / 1.732 ≈ 4619 kg. Option 4000 kg incorrectly divides the load by the number of legs without considering the angle.
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Question explanations
- According to most Canadian provincial regulations, who is ultimately responsible for the safe operation of a c
- A crane's rated capacity decreases as the load radius:
- What is the minimum number of full wraps of wire rope that must remain on a hoist drum when the hook is in its
- Before setting up a mobile crane, what is the most important factor to assess regarding ground conditions?
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