Crane Operator Certification Exam Prep · Question
A 5,000 kg load is being lifted by a spreader beam with two slings attached to the load, each at a 60-degree angle from the horizontal. What is the approximate tension in each of these two slings?
Tension = (Load Weight / Number of Slings) / sin(Slings Angle to Horizontal). For a 5,000 kg load with 2 slings at 60 degrees: (5000 / 2) / sin(60) = 2500 / 0.8
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Question: A 5,000 kg load is being lifted by a spreader beam with two slings attached to the load, each at a 60-degree angle from the horizontal. What is the approximate tension in each of these two slings?
Answer options:
- 2,500 kg ✅ 2,887 kg
- 3,536 kg
- 5,000 kg
Correct answer: 2,887 kg
Explanation: Tension = (Load Weight / Number of Slings) / sin(Slings Angle to Horizontal). For a 5,000 kg load with 2 slings at 60 degrees: (5000 / 2) / sin(60) = 2500 / 0.866 = 2886.8 kg. Sling angle significantly increases load on slings.
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Question explanations
- According to most Canadian provincial regulations, who is ultimately responsible for the safe operation of a c
- A crane's rated capacity decreases as the load radius:
- What is the minimum number of full wraps of wire rope that must remain on a hoist drum when the hook is in its
- Before setting up a mobile crane, what is the most important factor to assess regarding ground conditions?
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