Firefighter Mechanical Aptitude · Question
A hydraulic rescue tool uses a small piston to exert force on a fluid, which then pushes on a larger piston. If the small piston has an area of 5 cm² and the large piston has an area of 50 cm², how much force does the large piston exert if the small piston is pushed with 100 N of force?
Pressure is transmitted equally: P1 = P2, so F1/A1 = F2/A2. 100 N / 5 cm² = F2 / 50 cm². F2 = (100 N / 5 cm²) * 50 cm² = 1000 N.
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Question: A hydraulic rescue tool uses a small piston to exert force on a fluid, which then pushes on a larger piston. If the small piston has an area of 5 cm² and the large piston has an area of 50 cm², how much force does the large piston exert if the small piston is pushed with 100 N of force?
Answer options:
- 100 N
- 500 N ✅ 1000 N
- 50 N
Correct answer: 1000 N
Explanation: Pressure is transmitted equally: P1 = P2, so F1/A1 = F2/A2. 100 N / 5 cm² = F2 / 50 cm². F2 = (100 N / 5 cm²) * 50 cm² = 1000 N.
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- Scenario 1: Which simple machine uses a fulcrum to multiply force or change the direction of force?
- Scenario 2: If a hydraulic jack has a small piston with an area of 5 cm² and a large piston with an area of 50
- Scenario 3: Which of the following would require the MOST force to move?
- Scenario 4: A rope is tied to a heavy box. Instead of pulling the box directly, a firefighter wraps the rope a
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