Heavy Duty Equipment Technician Red Seal Exam Prep · Question
A hydraulic system on a track hoe is rated for a maximum pressure of 30,000 kPa. If the pump delivers 150 L/min of flow, what is the theoretical hydraulic power developed by the pump in kilowatts (kW)?
Hydraulic power (in kW) = (Pressure in kPa * Flow in L/min) / 60,000. So, (30,000 kPa * 150 L/min) / 60,000 = 75 kW. This formula is critical for calculating hy
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Question: A hydraulic system on a track hoe is rated for a maximum pressure of 30,000 kPa. If the pump delivers 150 L/min of flow, what is the theoretical hydraulic power developed by the pump in kilowatts (kW)?
Answer options: ✅ 75 kW
- 7.5 kW
- 45 kW
- 450 kW
Correct answer: 75 kW
Explanation: Hydraulic power (in kW) = (Pressure in kPa * Flow in L/min) / 60,000. So, (30,000 kPa * 150 L/min) / 60,000 = 75 kW. This formula is critical for calculating hydraulic power output.
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