CFAA Fire Alarm Technician · Question
Two 100 Ohm notification appliances are connected in parallel. What is the total equivalent resistance?
For two parallel resistors: (R1 x R2) / (R1 + R2) = (100 x 100) / (200) = 10,000 / 200 = 50 Ohms. 100/2 = 50.
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Question: Two 100 Ohm notification appliances are connected in parallel. What is the total equivalent resistance?
Answer options:
- 200 Ω ✅ 50 Ω
- 100 Ω
- 25 Ω
Correct answer: 50 Ω
Explanation: For two parallel resistors: (R1 x R2) / (R1 + R2) = (100 x 100) / (200) = 10,000 / 200 = 50 Ohms. 100/2 = 50.
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Question explanations
- The primary power for a fire alarm system must be:
- If a 120VAC primary power circuit for a fire alarm control unit is consuming 60 Watts of power, what is the cu
- In a steady-state DC circuit, if the conductor length is doubled while maintaining voltage and wire gauge, wha
- A resistor is rated at 10 Watts at 24VDC. If the voltage drops to 20VDC, what is the new power dissipation?
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