Electrician Red Seal · Question
The primary winding of a transformer is connected to 600V and draws 10A. If the transformer is 95% efficient and the secondary voltage is 240V, what is the maximum available current on the secondary?
First, calculate the input power: P_in = V × I = 600V × 10A = 6000 VA. Next, calculate the output power considering efficiency: P_out = P_in × efficiency = 6000
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Question: The primary winding of a transformer is connected to 600V and draws 10A. If the transformer is 95% efficient and the secondary voltage is 240V, what is the maximum available current on the secondary?
Answer options:
- 25.0 A ✅ 23.75 A
- 22.5 A
- 20.8 A
Correct answer: 23.75 A
Explanation: First, calculate the input power: P_in = V × I = 600V × 10A = 6000 VA. Next, calculate the output power considering efficiency: P_out = P_in × efficiency = 6000 VA × 0.95 = 5700 VA. Finally, calculate the secondary current: I_sec = P_out / V_sec = 5700 VA / 240V = 23.75 A.
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