Electrician Red Seal · Question
A 240 V, single-phase water heater element has a resistance of 12 Ω. What is the approximate current drawn by the element when it is energized?
Using Ohm's Law, Current (I) = Voltage (V) / Resistance (R). So, I = 240 V / 12 Ω = 20 A. This calculation directly determines the current draw for a resistive
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Question: A 240 V, single-phase water heater element has a resistance of 12 Ω. What is the approximate current drawn by the element when it is energized?
Answer options:
- 5 A
- 10 A ✅ 20 A
- 30 A
Correct answer: 20 A
Explanation: Using Ohm's Law, Current (I) = Voltage (V) / Resistance (R). So, I = 240 V / 12 Ω = 20 A. This calculation directly determines the current draw for a resistive load given voltage and resistance.
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- A residential garage is to be wired with a 15 A, 120 V duplex receptacle. According to the Canadian Electrical
- During a renovation of a commercial kitchen, an electrician needs to replace an old single-phase, 240 V, 5 kW
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