Electrician Red Seal · Question
The synchronous speed of a 4-pole, 60 Hz AC induction motor is:
The formula for synchronous speed is Ns = (120 × f) / P, where f is the frequency and P is the number of poles. Therefore, Ns = (120 × 60 Hz) / 4 poles = 7200 /
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Question: The synchronous speed of a 4-pole, 60 Hz AC induction motor is:
Answer options:
- 3600 RPM ✅ 1800 RPM
- 1200 RPM
- 900 RPM
Correct answer: 1800 RPM
Explanation: The formula for synchronous speed is Ns = (120 × f) / P, where f is the frequency and P is the number of poles. Therefore, Ns = (120 × 60 Hz) / 4 poles = 7200 / 4 = 1800 RPM.
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